![]() You could simply minus the years but quarters would be more tricky. select (col2::date)- (col1::date) from tablename. SELECT startDate, endDate, DATEDIFF ( endDate, startDate ) AS diffdays, CAST ( monthsbetween ( endDate, startDate ) AS INT ) AS diffmonths FROM yourTable ORDER BY 1 There are also year and quarter functions for determining the year and quarter of a date respectively. For ex, if you want the difference between two col, try the following query. ![]() ![]() DAY, MONTH, SECOND) or a string literal ( 'day', 'month', 'second'), but date_diff() only accepts string literal interval representations. Depending on the flavour of SQL, you need to cast the string values in date type and then you can perform subtraction. A curious difference between the two functions is that DATEDIFF will accept either a raw interval for its first argument (e.g. , date_diff('day', ''::DATE, ''::DATE) AS date_diff_outputĪWS provides documentation on DATEDIFF(), however no record of date_diff() appears to exist within either Redshift or PostgreSQL documentation. , datediff('day', ''::DATE, ''::DATE) AS datediff_str_literal_output Likewise is there any function in redshift that I. Mysql has a function called Week () where we can use the mode to get the desired result. Considering Sunday as the first day of the week the below statements in redshift should return 2 as the week number instead returning 1. The following code snippet provides an example of this behavior: SELECT datediff(DAYS, ''::DATE, ''::DATE) AS datediff_interval_output Amazon - Redshift : Week number for a given date is coming wrong. Here first argument is ‘Day’ which means datediff will calculate the day difference between the current date and the mentioned date and returns the output. we were trying to find the min max and avg of the ltrim-dateadd-datediff and it was too expensive on 300 million rows to be useful even as a one-off solution. For example, because the common calendar starts from the year 1, the first decade (decade 1) is through, and the second decade (decade 2) is through. The default column name for the DATEDIFF function is DATEDIFF. You can name date parts in full or abbreviate them. This example assumes that the current date is June 5, 2008. It appears that Redshift supports two possible functions for computing a time interval distance between two DATE-like objects: DATEDIFF() & date_diff(). DATEDIFF('day', currentdate, ' 11:00:00') AS 'DATE DIFFERENCE' / - DateDiff- / Here we have mentioned the in-built function in the statement. this seems neat, i did find that is was less performant than our needs required. Amazon Redshift interprets the DECADE or DECADES DATEPART based on the common calendar. The following example finds the difference, in number of quarters, between a literal value in the past and today's date.
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